How small would a calculator have to be to become a black hol?

Yes, the typo was on purpose.

I didn’t know what to do today, so I did this.

The Schwarzschild radius is calculated by:

{\displaystyle r_{s}={\frac {2GM}{c^{2}}},}

Where G is the gravitational constant of 6.67408 × 10-11 m3 kg-1 s-2, M is the mass of the object, and c is the speed of light.

Assuming a calculator weighs about 100 grams, the radius is 2*6.67408 × 10-11 m3 kg-1 s-2*100/8.98755179 × 1016 m2 / s2 and it’s so low, let’s take the Sun.

The Schwarzschild radius of the Sun is about 3km. Now, for 100g, that’s 5*10^-32 times the mass of the Sun, or 1/500000000000000000000000000000000. 1/500000000000000000000000000000000 of 3km is 0.00015 yoctometers. At that rate, the calculator will be extremely, extremely, logarithmically smaller than the nucleus of an atom.

Then, it will consume us all. To whatever happens when you get sucked into a tiny black hole.



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